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Topic: Unknown Solid  (Read 1723 times)

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Offline kevin_lofgren

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Unknown Solid
« on: September 15, 2015, 10:47:18 PM »
I'm trying to get some help with this unknown compound. The C-13 NMR has two peaks.  One of the peaks is for aromatic carbons. I know this because aromaticity is evident in the IR NMR and is the only stretch on my H NMR chart (singlet).  The other C-13 stretch is at around 95. I don't know what that peak is from!!!  The compound is soluble in 5% sodium hydroxide and ether. It's not soluble in 5% hydrochloric acid, water and 30% sulfuric acid. It appeared to be slightly soluble in 5% sodium bicarbonate.  Since it dissolves in two bases I would assume that there is something like an oxygen or nitrogen with a hydrogen that could be removed. Also, sodium fusion showed the compound contains no nitrogen, sulfur or halogens. What should my next step be???  Thanks! 

Offline kevin_lofgren

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Re: Unknown Solid
« Reply #1 on: September 15, 2015, 11:03:03 PM »
I feel like there must be more than one aromatic ring. 

Offline MOTOBALL

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Re: Unknown Solid
« Reply #2 on: September 16, 2015, 11:43:39 AM »
1. Elemental analysis; this will let you calculate molecular formula

2. Molecular formula will enable you to determine the number of rings & double bonds (i.e. degrees of unsaturation)

3. Mass spectrum will (a) confirm Mol. Wt. (b) detect characteristic structural features

4. Proton NMR for determination of different H environments

Combine ALL information to obtain a structure that is consistent with ALL data.

Good Luck.

Offline kevin_lofgren

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Re: Unknown Solid
« Reply #3 on: September 17, 2015, 03:14:11 AM »
Thanks for the reply. I also found out why I was having so much trouble trying to determine the structure...he gave me the wrong C-13 and H NMR for my compound!!  Glad that is resolved.

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