I have problem using the ester of l-alanine because, after using this ester, I'm getting COOR group of that ester instead of COOH. Here, COOH group is necessary to be there in my michael adduct as in the next step after this addition, COOH should be there in that next step final product.
Like, after the addition reaction, only reducing the C=O to CH2 & getting the final product as : Ph-CH2-CH2-CH(COOC2H5)-NH-CH(CH3)-COOH