Hi,
The Question is:
'Calculate the proportions of [Mn(
12CO)
6] + and [Mn(
12CO)
5(
13CO)]
+ present in a sample of [Mn(CO)
6]
+ containing naturally abundant carbon. Sketch the appearance of the solution-phase
55Mn NMR spectrum of [Mn(CO)
6]
+ , taking into account these two calculated proportions. Ensure that in your answer you fully account for the number and relative intensities of the peaks in the spectrum.'
Abundance of 12C = 0.989
Abundance of 13C = 0.011
To calculate the proportion of [Mn(
12CO)
6]
+ :
(0.989)^6 = 0.9358
To calculate the proportion of [Mn(
12CO)
5(
13CO)]
+ :
(0.989)
5 * (0.011) = 0.01041
If the answers for the proportions are correct, I would get the
55Mn NMR spectrum of [Mn(CO)
6]
+ to consist of:
A large central singlet with relative intensity of 0.9358. Corresponding to [Mn(
12CO)
6]
+A doublet of satellite peaks, a peak either side of the central singlet. Each peak would have an intensity of (0.01041/2). Corresponding to [Mn(
12CO)
5(
13CO)]
+Can anyone tell me if my way of calculating the probabilities of this is correct, and if it is, is my description of the manganese NMR spectrum correct ? I'mm pretty confident it's right.
Appreaciate any feedback,
Mark