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Topic: Dissociation of PO at 200-2000K  (Read 3307 times)

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Offline Rmerckx

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Dissociation of PO at 200-2000K
« on: December 13, 2015, 06:41:04 PM »
This is a question I got in molecular Physical Chemistry. This course deals with statistical thermodynamics. I have to determine the degree of dissociation of PO in the temperature range 200K-2000 K at a pressure of 1000 Pa. Anyone who can help me with this exercise? I don't see the reaction scheme. My thoughts were : 4PO ::equil:: P_4 + 2O_2 But this gives me a 4Th order equation which i can't solve. or 2PO  ::equil:: P_2+O_2
thanks ! :)

Offline Corribus

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Re: Dissociation of PO at 200-2000K
« Reply #1 on: December 14, 2015, 10:38:24 AM »
Can you provide the actual wording of the question (verbatim)?
What men are poets who can speak of Jupiter if he were like a man, but if he is an immense spinning sphere of methane and ammonia must be silent?  - Richard P. Feynman

Offline Enthalpy

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Re: Dissociation of PO at 200-2000K
« Reply #2 on: December 17, 2015, 08:30:01 AM »
I've run Propep, a software for chemical equilibria in flames, on 16g oxygen and 31g phosphorus at 1kPa. Here under are the molar fractions.

========== 2000K ==========

O                    1.3200e-005
O2                   3.8964e-006
P                    1.0580e-003
PO                   8.0473e-001
PO2                  9.1652e-002
P2                   6.4740e-002
P2O3                 3.7638e-002
P2O4                 1.4476e-004
P2O5                 1.7093e-005
P3                   2.1799e-006
P3O6                 8.6031e-007
P4                   6.3651e-007

All gaseous.

========== 1000K ==========

PO                   2.0054e-005
PO2                  6.0515e-007
P2                   7.2306e-002
P2O3                 2.0800e-002
P2O4                 1.1807e-005
P3                   2.5759e-006
P3O6                 2.0438e-004
P4                   4.7768e-001
P4O6                 2.0417e-007
P4O7                 9.8869e-003
P4O8                 1.1812e-001
P4O9                 2.7708e-001
P4O10                2.3877e-002

All gaseous.

========== 500K ==========

P2                   9.4437e-008
P4                   5.5551e-001
P4O7                 1.5300e-004
P4O8                 2.5238e-002
P4O9                 3.9715e-001
P4O10                2.1943e-002

All gaseous.

========== 390K ==========

P4                   5.9817e-001
P4O7                 1.3182e-006
P4O8                 6.4889e-004
P4O9                 2.0281e-002
P4O10                5.9193e-004
Condensed species
P4O10(cr)            3.8031e-001

========== 200K ==========

Software fails. I suppose all products are solid or liquid, then Propep can't solve.

=========================

You can trust Propep's results when available. Especially, it finds autonomously the right produced species from its included base, which must be pretty complete for P and O. Though, it finds strictly equilibria, be there a credible reaction path to them or not. For instance, I suppose PO stays untouched at 200K, but from the equilibrium it's absent.

I can't imagine how to obtain by hand the above results. At some temperatures the alternatives to PO are PO2, P2 and P2O3, and others it's P4, P4O9 and P4O8, still at other T solid P4O10 meddles in.

Offline Rmerckx

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Re: Dissociation of PO at 200-2000K
« Reply #3 on: December 18, 2015, 09:37:50 AM »
Can you provide the actual wording of the question (verbatim)?
This is the actual question:
Questions in series B deal with calculating equilibrium constants of gas phase reactions using
statistical thermodynamics and using them to determine an equilibrium composition.
Determine the degree of dissociation of PO in the temperature range 200–2000 K at a pressure
of 1000 Pa.

Offline Enthalpy

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Re: Dissociation of PO at 200-2000K
« Reply #4 on: December 21, 2015, 01:52:50 PM »
That's better. "Dissociation" means into oxygen and phosphorus, from the available PO. Once you've chosen the molecular formula for oxygen and phosphorus, it's a simple equilibrium, not influenced by the other combinations provided you suppose some pressure.

I still fear that the person who asked this just ignores how many compounds are possible, so to get a good mark you'll need more diplomacy than what I am capable of.

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