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Topic: Balancing redox equation  (Read 2432 times)

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Offline elfishies

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Balancing redox equation
« on: January 30, 2016, 07:39:22 PM »
How do you balance this equation?

IO3{-} + I{-} + H{+} = I3{-} + H2O

I tried using oxidation numbers but there seems to only be reduction?
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Offline mikasaur

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Re: Balancing redox equation
« Reply #1 on: January 30, 2016, 08:20:11 PM »
What do you consider to be the reduction?

Do you think there might be an oxidation going on as well?
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Offline elfishies

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Re: Balancing redox equation
« Reply #2 on: January 30, 2016, 08:56:29 PM »
reduction: IO3- --> I3-
the oxidation number for I goes from +5 to -1

sorry, I can't seem to see any oxidation reaction

***edit: I think I figured it out, thanks!***
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Offline mikasaur

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Re: Balancing redox equation
« Reply #3 on: January 30, 2016, 09:28:36 PM »
Did you? Nice!

Mind showing us what you did (at least the first couple steps)?
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Offline AWK

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Re: Balancing redox equation
« Reply #4 on: January 31, 2016, 02:22:32 AM »
Oxidation number of iodine in I3- is not equal to -1
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Offline Hunter2

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Re: Balancing redox equation
« Reply #5 on: January 31, 2016, 01:32:27 PM »
One more hint:
Check what is I3-. Divide this molecule fpr easier calculation.
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