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Topic: Help Balancing Ion-Electron Redox Half-Reaction  (Read 2282 times)

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Offline bobbybeck

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Help Balancing Ion-Electron Redox Half-Reaction
« on: April 16, 2016, 08:17:49 PM »
Hello. I was wondering if anyone could help me balance this equation using the methods I said in the subject line. Thanks!

IO3-(aq) + I-(aq) = I3-(aq)

This is an acidic reaction, I don't know if that is obvious or not.

Offline Burner

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Re: Help Balancing Ion-Electron Redox Half-Reaction
« Reply #1 on: April 16, 2016, 10:04:53 PM »
Hello. I was wondering if anyone could help me balance this equation using the methods I said in the subject line. Thanks!

If I didn't misread your post, you want to balance this quation using half-equation method, right?(Just for confirmation - not saying this method is wrong)

IO3-(aq) + I-(aq) = I3-(aq)

Obviously, you have IO3-(aq) and I-(aq) from the start, and these two chemicals will both be oxidized/reduced to I3-(aq). So, you need to balance the following two half equations:

IO3-(aq)  :rarrow: I3-(aq)

I-(aq)  :rarrow: I3-(aq)

Try to proceed from here.
Year 1 science student in HKUST and a Chemistry geek.
If I make any mistakes in the forum, please don't hesitate to correct me as I want to learn.

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