Hello,
I am undergraduate student. I will be doing a chemistry experiment tomorrow for my school's chemistry club. The demonstration is the burning of trimethyl borate, which, produces a green flame. Unfortently my school's chemistry club does not have any money and so I found out online that if I burn a small amount of methonal with either sodium borate or boric acid a small amount of trimethyl borate is produced which then immediately burns and produces the green flame, albeit this method is less spectacular.
I am hoping to demonstrate with chemical formulas to the club the chemistry of what is going on both with the methonal and sodium borate burning to produce trimethyl borate4 and also burning methonal with boric acid to produce trimethyl borate. I know the chemical formulas of the reactants. Just not the products. Lastly I also want to know what are the products of burning trimethyl borate. Thank you for your help.
Here is what I do know:
Sodium Borate
Chemical Formula: Na2B4O7·10H2O or Na2[B4O5(OH)4]·8H2O
Boric Acid:
Chemical formula: BH3O3
IUPAC: Trihydrooxidoboron
Structure: It appears as three alcohol groups coming off of Boron
Trimethyl Borate
Chemical Formula: C3H9BO3
What I think is happening is that in the case of boric acid and methanol it appears that the hydrogens on the boric acid are being replaced by methyl groups to produce trimethyl borate. However, I have no idea what is the process for with of these reactions.