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Topic: Whatmass of P4 is needed toProduce 500g of PF3 if the reaction has a 36.4% yield  (Read 1486 times)

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Offline ChargePositive

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Whatmass of P4 is needed toProduce 500g of PF3 if the reaction has a 36.4% yield
« on: October 23, 2016, 08:09:10 PM »
What mass of P4 is needed to produce 500g of PF3 if the reaction has a 36.4% yield?

The equation is:
P4 + 6F2 --> 4PF3

I just need the starting amount of PF3 to do the stoichiometry.

Thanks

---------------------------------
Current Attempt: (Which I know I messed up somewhere)

182g PF3  ____1mol PF3_____ * ____1mol P____ * ___30.974g P___   =
              ____87.968g PF3__    ____4mol PF3__    ____1mol P_____
« Last Edit: October 23, 2016, 09:58:48 PM by ChargePositive »
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Offline Borek

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Re: Whatmass of P4 is needed toProduce 500g of PF3 if the reaction has a 36.4% yield
« Reply #1 on: October 24, 2016, 03:23:49 AM »
Why starting amount of PF3, if PF3 is your product?

Initially don't bother with the yield.

How many moles of PF3 are to be produced?

How many moles of P4 needed for that?
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