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Topic: Iodine addition on alkenes  (Read 7728 times)

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Offline mir

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Iodine addition on alkenes
« on: May 26, 2006, 10:16:17 AM »
I guess I have figured out the upper mechanism.
But the lower reaction is causing me to bite my nails and drinking to much coffee. All in all, I need help. On monday I have an oral exam in physcial org chemistry :-/
No single thing abides, but all things flow.
Fragment to fragment clings, and thus they grow
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Offline Dan

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Re: Iodine addition on alkenes
« Reply #1 on: May 26, 2006, 11:19:10 AM »
How about this:

1. Form the iodonium ion as normal
2. Decarboxylate to open the 3 mem ring
OR
Open to give the tertiary carbocaton, which is rapidly trapped by the CO2H, forming a 4 membered ring
Reverse [2+2] cycloaddition, eliminating CO2

3. SN2 by water
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Offline Dan

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Re: Iodine addition on alkenes
« Reply #2 on: May 26, 2006, 11:53:26 AM »
Like this http://users.ox.ac.uk/~some1599/Images/mech.jpg

It's a bit scruffy, but I had to use use paint, so...
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Offline movies

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Re: Iodine addition on alkenes
« Reply #3 on: May 26, 2006, 01:17:33 PM »
How about just forming the diiodide, then deacarboxylate and eliminate one of the I's, then SN2 (or SN2') with water to displace the other.

Offline Dan

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Re: Iodine addition on alkenes
« Reply #4 on: May 26, 2006, 02:19:08 PM »
Yeah that seems more likely, seeing as KI about, good call.
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Offline mir

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Re: Iodine addition on alkenes
« Reply #5 on: May 26, 2006, 04:58:38 PM »
How about just forming the diiodide, then deacarboxylate and eliminate one of the I's, then SN2 (or SN2') with water to displace the other.

Like this?

I wasnt sure about the decarboxylation step.
I understand now. In such problems, you have to dare to use the imagination.
Even if you have to form a sterically extreme cyclobutane-like ring.
No single thing abides, but all things flow.
Fragment to fragment clings, and thus they grow
Until we know and name them.
Then by degrees they change and are no more
The things we know.
- Titus Lucretius Carus

http://www.ife.no

Offline movies

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Re: Iodine addition on alkenes
« Reply #6 on: May 28, 2006, 06:51:52 PM »
Not quite, I was thinking that the second compound you have drawn there would decarboxylate with the electrons from the C-C bond that you would break kicking down to diplace the adjacent I and from the C=C double bond.

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