If it helps, the buffer solution was made by mixing 1 M Na2HPO4 and 1 M NaH2PO4 with distilled water. With the pH of 6 buffer, it was 12 mL Na2HPO4 and 88 mL of NaH2PO4. Then it was diluted to 1 L. Would that be considered the original composition? If so, how can I calculate how many mL of the pH of 6 buffer I should add to the growth medium so that it changes to a pH of 7.8 to a pH of 6?
If that does not work, do you have a suggestion with how much mL of the buffer solution I should add to the 15 mL of the growth medium so that the pH is irrelevant? Thanks for the help.