[candiishop]

I have trouble writing:

1. Dissolution equation of a solid
2. Hydrolysis reaction(s) equations responisble for any observed change in pH of solution


a) Ammonium iron(II) sulfate
1. (NH4)2 Fe(S04)2 (s) -------> 2NH4+ (aq) + Fe2+ (aq) + 2SO4 2- (aq)

I don't understand the charge (valencies) to get the compound of ammonium iron (III) sulfate ie (NH4)2 Fe(S04)2 

2. In the experiment the pH was 4
- [Fe(H20)6]2+ (aq) + H20 (l) <------> [Fe(H2O)5OH]+ (aq) + H3O+ (aq)

I don't know how to get [Fe(H20)6]2+ especially 6 times of water

b) Ammonium iron(III) sulfate pH was 4

c) Glycine

1. NH2CH2COOH (s) ----> NH2CH2COOH
2.

[Dan]

It isn't clear to me what you are actually asking here.

I don't understand the charge (valencies) to get the compound of ammonium iron (III) sulfate ie (NH4)2 Fe(S04)2 

(NH₄)₂ Fe(S0₄)₂ is ammonium iron (II) sulfate
(NH₄)Fe(S0₄)₂ is ammonium iron (III) sulfate

I don't know how to get [Fe(H20)6]2+ especially 6 times of water

Fe²⁺ + 6H₂O -----> Fe(H₂O)₆²⁺

[AWK]

I don't understand the charge (valencies) to get the compound of ammonium iron (III) sulfate ie (NH4)2 Fe(S04)2

should be
 (NH4) Fe(S04)2 or  (NH4)2S04.Fe2(S04)3

Cations Fe with water are formed during dissolution iof anhydrous salts in water, hydrated salts contain water even in solid state.

Glycine is in form of H3N(+)CH2COO-