[xxdakee]

Al2S3 + 6H2O = 2Al(OH)3 + 3H2S
Can someone explain this reaction to me? Why this is a hydrolysis? And why Al2O3 can't be a product of this reaction instead of Al(OH)3?


I'm 100% sure that this reaction is correct, but I can't find any argument to prove it.

[AWK]

Do you know a definition of hydrolysis?

[xxdakee]

Yes I know

[AWK]

Then this reaction should be obvious.

[xxdakee]

But for my teacher its not lol. She said that the products of this reaction are Al2O3 and H2S

[AWK]

When you treat Al₂S₃ with water vapors at temperature over 400 C then anhydrous Al₂O₃ is formed. Formation of boehmite (AlOOH) starts about 200 C.
Since Al(OH)₃ always contains some water its formula is sometimes written as Al₂O₃·nH₂O. But without H₂O below 400 C it is a nonsense.

[xxdakee]

Thanks That's all I need