Amounts of tin may be alloyed with copper to produce bronzes of varying composition and properties.
4.4464 g of a particular bronze, compounded of only Cu and Sn, can be quantitatively converted into a 5.5860-g mixture of the oxides CuO and SnO2.
What was the percentage (by mass) of tin in the alloy?
%
I did it but it's wrong. What did I did wrong? And how do I do this question?
Z g= Cu Y g= Sn
Zg x (1mol Cu/ 63.53gCu) x (79.35g CuO/ 1mol CuO) = 1.2525X g Cu
Yg x (1mol Sn/ 118.69g Sn) x ( 150.69g SnO2/1 mol of SnO2) = 1.2696Y g Sn
1.2525X + 1.2696Y = 5.586
X + Y = 4.4464.
1.2525(4.4464-Y) + 1.2696Y = 5.586
5.569 - 1.2525Y + 1.2696Y = 5.586
0.0171Y = 0.0166
Y=0.9707
0.9707/4.4464 x 100% = 21.83%