[mycattypes]

Hi there, I have a question about a very important chemistry homework question I have.
Would someone please be able to solve this and give me an explanation as to how you came about your answer? I would be so grateful. Thanks!
Consider the reaction
CaCN2 + 3 H2O → CaCO3 + 2 NH3 ,
which has a 45.6% yield. How much H2O is
needed to produce 16.3 moles of CaCO3?
1. 107 g
2. 22.3 g
3. 48.9 g
4. 1930 g
5. 880 g
6. 401 g

[AWK]

http://www.chemicalforums.com/index.php?topic=65859.0

[Hunter2]

Hi there, I have a question about a very important chemistry homework question I have.
Would someone please be able to solve this and give me an explanation as to how you came about your answer? I would be so grateful. Thanks!
Consider the reaction
CaCN2 + 3 H2O → CaCO3 + 2 NH3 ,
which has a 45.6% yield. How much H2O is
needed to produce 16.3 moles of CaCO3?
1. 107 g
2. 22.3 g
3. 48.9 g
4. 1930 g
5. 880 g
6. 401 g

1. Check according the equation how much mole water correspondes to the Calciumcarbonate , calculate this to the given moles.
2. Convert this to the mass
3. Calculate value with the yield

Now its yout turn