[Vultux]

I calculated the moles of Oxygen and methane gas, not the products.

[hypervalent_iodine]

I calculated the moles of Oxygen and methane gas, not the products.

Okay, so how did you know how many moles of oxygen you needed in that question? What concepts did you use to arrive at that conclusion?

[Vultux]

I started with methane gas molecules and converted that to methane moles. I then used that and set up the mole ratio and used that to get to moles of oxygen.

[hypervalent_iodine]

I started with methane gas molecules and converted that to methane moles. I then used that and set up the mole ratio and used that to get to moles of oxygen.

Okay then, so if we just take that to start with. The mole ratios you used can also be utilised to work out the moles of products. That's why we put coefficients out front of the products as well as the reactants.

[Vultux]

So the CH₄ moles are 1.40*10^-4 and Oxygen is 2.8*10^-4. Do I convert them to grams and find the lowest number?

[hypervalent_iodine]

So the CH₄ moles are 1.40*10^-4 and Oxygen is 2.8*10^-4. Do I convert them to grams and find the lowest number?

The question is a bit vague on that front. It wouldn't matter, though. It's going to be the same whether you take the lowest number of moles, or lowest number of grams.

[Vultux]

So it's CH₄. Now after I multiply it by 4, what do I do next?

[hypervalent_iodine]

So it's CH₄. Now after I multiply it by 4, what do I do next?

I'm not doing your assignment for you. Refer to previous posts in this thread on limiting reagents, as well as the posts in the other forum you are posting in.