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Topic: nuclear equation with ?  (Read 9946 times)

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Offline Edher

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nuclear equation with ?
« on: May 13, 2006, 09:47:35 PM »
Saludos,

      I am not quite sure what they are asking for in this problem, could you please help me get started.

Write a balanced nuclear equation for the following:

21282Pb (3115P, ?)


Here is my attempt:

21282 -->  3115P + 16366Dy + 0+1?

Does it matter that the mass number doesn't match?

Thank you,
Edher
« Last Edit: May 13, 2006, 10:01:00 PM by Edher »

Offline Grejak

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Re: nuclear equation with ?
« Reply #1 on: May 14, 2006, 12:57:26 AM »
I've never heard of a ? exit channel...

It does matter that the mass numbers do not match.  In any nuclear decay or reaction, both the mass and the atomic numbers must add up properly on both sides of the equation.  Also, it appears that you are incorrectly reading the reaction notation.  What you have written is something commonly used to denote nuclear reactions where 21282Pb is the target 3115P is the projectile or entrance channel and ? is the exit channel.  Another way to write is the first reaction you have is:

21282Pb+3115P -> X + ?

Anyway, the reaction you have written does not tell you whether the exit channel is ?+ or ?-, so there are two possibilities.  One is:
21282Pb(3115P,0-1?-)24398Cf

or in more understandable notation:
21282Pb+3115P -> 24398Cf + 0-1?- 

If you really want to be correct, you can throw an antineutrino into the right side of that equation :)

Is the first reaction that you have written down correct though?  Based on my understanding of nuclear reactions (So I may not be correct) I do not think that it is possible for a ? exit channel to exist and 21282Pb has a half-life of 10.64 hours, so there is no way that anyone will allow you to make a target out of that.
« Last Edit: May 14, 2006, 12:59:09 AM by Grejak »

Offline Mitch

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Re: nuclear equation with ?
« Reply #2 on: May 14, 2006, 03:52:08 AM »
I'm with Grejak except 243Cf would decay by positron emission for beta-decay.

http://www.isotope-table.com/
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