[eddystone]

Hi all,

Is there anyone out there smart enough to answer this question???

"Show how you could make the following compound in the lab"

              O
   (Double bond from C to O)
CH3 CH2 C O CH2 CH3

Thanks heaps
eddy

[Demotivator]

One way is by oxidation of a secondary alcohol (3-pentanol) by an oxidizing agent.
CH3 CH2 C(H)(OH) CH2 CH3 + H2CrO4 in acetic acid or acetone solvent

[movies]

I think that the product is supposed to be the ester, but the drawing isn't really clear.  Demotivator's way will certainly work for the ketone.

For the ester, The easiest way is probably from propionic acid and ethanol with catalytic acid (a Fisher Esterification).  Similarly you could start from 1-propanol and do an oxidation as Demotivation suggested to give propionic acid.  You could convert that acid to the acid chloride too, and then react that with ethanol.

Lots of ways to do it!

[Demotivator]

You're right. I thought it was the ketone. I missed the O on top so it must be the  ester.

[haiph12]

CH3CH2COOH + CH3Ch2OH ( ctalyst  H2SO4 s )  ---  production
or
CH3CH2COCl  +  CH3CH2ONa ---  pro