Determine the concentration of sulfate if 1g of pyrite oxidizes in 1L of water.
Here is my attempt at answering. Can someone let me know if i'm right please.
FeS2 + 7/2 H2O + 15/4 O2 = 2SO4 + Fe(OH)3 + 4H+
1000 mg/l pyrite = 8.33 mM (1000mg/l / 120g/mol)
1:2 ratio between FeS2 and SO4 8.33 mM*2 = 16.66mM sulfate produced
Thank you.