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Topic: Help with this Grignard Reaction  (Read 2696 times)

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Offline Firehchicken

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Help with this Grignard Reaction
« on: January 29, 2018, 02:55:19 AM »
I just cannot see how the benzene connects to the di-ketone-ether (whatever name that compound is). ??? ??? ???


Offline zarhym

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Re: Help with this Grignard Reaction
« Reply #1 on: January 29, 2018, 03:26:57 AM »
This is a two step reaction.

First step, you will have acetophenone.
Second step, your SM will react with acetophenone to form the product.

You should be able to draw it out.
Otherwise, you will have troubles in your exam.

Offline Firehchicken

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Re: Help with this Grignard Reaction
« Reply #2 on: January 29, 2018, 03:36:59 AM »
This is a two step reaction.

First step, you will have acetophenone.
Second step, your SM will react with acetophenone to form the product.

You should be able to draw it out.
Otherwise, you will have troubles in your exam.

What's SM?

Offline zarhym

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Re: Help with this Grignard Reaction
« Reply #3 on: January 29, 2018, 03:39:05 AM »
Starting Material

Offline Firehchicken

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Re: Help with this Grignard Reaction
« Reply #4 on: January 29, 2018, 04:11:37 AM »
Starting Material

So molecule (1) will react with acetophenone to form the product? Right thanks for the help

Offline chenbeier

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Re: Help with this Grignard Reaction
« Reply #5 on: January 29, 2018, 04:28:49 AM »
What you describe as a Ether ketone is Acetic acid anhydride

Offline zarhym

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Re: Help with this Grignard Reaction
« Reply #6 on: January 29, 2018, 04:59:59 AM »
Starting Material

So molecule (1) will react with acetophenone to form the product? Right thanks for the help

Your grignard starting material will react with acetophone. This is the reason it is the excess one.


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