December 24, 2024, 07:31:36 AM
Forum Rules: Read This Before Posting


Topic: Correct formula for 2nd-order half life  (Read 2674 times)

0 Members and 1 Guest are viewing this topic.

Offline Firehchicken

  • Regular Member
  • ***
  • Posts: 24
  • Mole Snacks: +0/-0
Correct formula for 2nd-order half life
« on: January 26, 2018, 07:57:03 AM »
I have seen two formulas for 2nd order half lifes:

1/2*k*[initial concentration]

1/k*[initial concentration]

Which one is correct

Offline mjc123

  • Chemist
  • Sr. Member
  • *
  • Posts: 2074
  • Mole Snacks: +302/-12
Re: Correct formula for 2nd-order half life
« Reply #1 on: January 26, 2018, 08:34:43 AM »
Neither is absolutely correct. It depends on the definition of k. How do you write the rate equation?

Offline Firehchicken

  • Regular Member
  • ***
  • Posts: 24
  • Mole Snacks: +0/-0
Re: Correct formula for 2nd-order half life
« Reply #2 on: January 26, 2018, 09:39:54 AM »
Neither is absolutely correct. It depends on the definition of k. How do you write the rate equation?

They didn't give the rate equation, just the value of the rate constant.

Offline mjc123

  • Chemist
  • Sr. Member
  • *
  • Posts: 2074
  • Mole Snacks: +302/-12
Re: Correct formula for 2nd-order half life
« Reply #3 on: January 26, 2018, 11:38:04 AM »
Well that is very naughty of them. Do they give a reaction equation? If so you must assume that the rate is defined in terms of that equation, and
Rate = (1/α)*d[X]/dt
where α is the coefficient of reagent X in the equation (negative for reactants, positive for products).
So if the equation is, say, 2A  :rarrow: B and
Rate = (-1/2)*d[A]/dt = k[A]2
then d[A]/dt = -2k[A]2
If, however, you write (as I would) d[A]/dt = -k'[A]2
then obviously k' = 2k
Now solve the differential equation and get the half-life, and you get
t1/2 = 1/(k'[A]0) = 1/(2k[A]0)

Sponsored Links