[h_loyali]

I mixed 10.00 ml NH4CL with water and transferred 20 ml NH4CL + 20 NAOH(0.3 M) to flasks and titrated it with 15 ml HCL. Concentraion of sodium Hydroxide is 0.3515 M and Concentraion of HCL is 0.2676 M. Now want to know :

a) If the concentration of the original ammonium chloride solution was half what it was in myexperiment, would more or less hydrochloric acid be required to reach the endpoint?

b) if the concentration of the original ammonium chloride solution was ten times what it was in my experiment, and the indicator was added, it immediately changed colour to yellow before any hydrochloric acid was added. what will happens?

Equitions:

NH4CL + NAOH = NH3 + H2O + NACL

HCl + NAOH = H2O + NACl


there is 1:1 mole ration between NH4CL and HCL . if NH4cl was half so we need half amount of HCL ?

b) if NH4CL was 10 times more why we don't need HCL to turn color?

[Borek]

I mixed 10.00 ml NH4CL with water

Something is missing here - NH₄Cl (pay attention to capitalization!) is not a liquid, so "10 mL" doesn't mean anything.

[h_loyali]

I mixed 10.00 ml NH4CL with water

Something is missing here - NH₄Cl (pay attention to capitalization!) is not a liquid, so "10 mL" doesn't mean anything.

It is Ammonium chloride.

[Borek]

I know what it is intended to be, but it still doesn't make what you wrote correct.

Have you forgot to mention the concentration?

[h_loyali]

I have to calculate the concentration of NH4Cl . What I got is 2.0M.

[Borek]

I have to calculate the concentration of NH4Cl . What I got is 2.0M.

OK, now we know what the experiment was about. But I need to ask you again for clarification:

I mixed 10.00 ml NH4CL with water and transferred 20 ml NH4CL + 20 NAOH(0.3 M) to flasks

You took 10 mL of the solution but mixed 20 mL? The procedure that you followed is still not clear.