Hi, this is the 1H NMR spectra of 2-cyanomethyl-N-methylbenzimidazole, there are 4 aromatic protons on the benzimidazole ring: 1H(DMSO, 300MHz): 7,63 (dd, J1=1,47 Hz, J2=7,41 Hz), 7,55 (dd, J1=1,47 Hz, J2=7,50 Hz), 7,27 (dt, J1=1,38 Hz, J2=7,50 Hz), 7,22 (dt, J1=1,39 Hz, J2=7,45 Hz) Why are the two signals on the right doublets of triplets? aren't they tiplet of doublets? coupling constants values are matching to td.
**mod wildfyr** split into a new topic, this had nothing to do with the original post.