a) If 65 mL of 1.00 M HCl is mixed with 35 mL of 1.00M NaOH, how many moles of each ion are present BEFORE the reaction?
So I understand that HCl + NaOH --> NaCl + H2O and that HCl = 0.065 mol and NaOH= 0.35 mol. I'm just a bit stuck as to how to calculate the individual ions. Please *delete me* Thank you!
Na+
Cl-
H30+
OH-
b) Which reactant is the limiting reagent
c) What are the final concentrations of all the ions present?
d) What is the pH of the final solution.
Thanks so much!