1) Consider the unit cell of aluminum with an aluminum ion every corner and every face-centered site of the cube. Using the value of ionic radius of aluminum ion r = 0.143 nm, the length of each edge of the unit cell can be calculated as ... nm.
2) Using the atomic weight value of aluminum 27.0, the density of aluminum can be calculated as ... g/cm^3
***Calculate into 2 significant figure***
For 1), I draw a picture and give edge length = x, then I use equation x^2+x^2 = (4r)^2
and I got x =0.404404 but the answer is 0.41, but if we consider into 2 sig figures it should be 0.40 right?
For 2), Valu = (4/3)*(22/7)*0.143*0.143*0.143
mass = 27, then density = 27/Valu and I got 2700
what is my mistake?