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Topic: redox in basic medium  (Read 1633 times)

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Offline rafarock077

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redox in basic medium
« on: November 16, 2018, 08:18:54 PM »
Hi, im needing some help in redox in basic medium.
   i can be wrong but the order to balance the half-reactions first you have to add electrons, then h20 and after oh right? but if both compounds have the same electric charge what shpuld i do? also, when i add oh everything that i balance before is useless because oh isnĀ“t neutral

 ty 4 the help :)

Offline Borek

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Re: redox in basic medium
« Reply #1 on: November 17, 2018, 04:06:20 AM »
You got it reversed, you should use OH-/H2O to balance atoms and then electrons to balance charge.
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Offline rafarock077

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Re: redox in basic medium
« Reply #2 on: November 17, 2018, 02:38:44 PM »
so for example in this case "C3 H8 0 - C3 H6 O" (both C3 H8 0 and C3 H6 O are neutrals)  first i add oh then h20 and after electrons right? so it end like this, if im not wrong "2oh + C3 H8 O -- C3H6 O + 2h20 + 2electrons" 

Offline Borek

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Re: redox in basic medium
« Reply #3 on: November 17, 2018, 05:50:51 PM »
Looks OK.

Please pay attention to formatting and correct capitalization, there is really no reason other than laziness to not show the equation as

C3H8O + 2OH- :rarrow: C3H6O + 2H2O + 2e-
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