In my research for a project, I have found a website that shows how an iodometric back titration can be used as a method to find the amount of caffeine. I have searched the forum, however I have not found a thread asking about this method; most threads are people using dichloromethane or ethyl acetate.
http://www.hkasme.org/News/818/Report_6B_Christiam%2520Alliance%2520SC%2520Chan%2520Memorial%2520Secondary%2520School_Chemical_test_for_caffeine.pdfI am confused as to how the chemical equation on page 7 exactly works.
C8H10N4O2 + 2I2 + KI + H2SO4 → C8H10N4O2.HI.I4 + KHSO4
1. What is the purpose of the added sulfuric acid? Is there a neutralization here?
http://www.chemicalforums.com/index.php?topic=61568.msg219758#msg219758- In this thread, it was said that caffeine needs acid to dissolve it in water, however, that there is already acid in tea? Is this a difference between the behavior of caffeine in tea versus coffee? If my sample is a sample of tea made with water, is there a need to add acid?
- If there is a neutralization, is the separated equation KI + H2SO4 → HI + KHSO4 ? If my sample is a sample of tea prepared with water, wouldn't HI form hydroiodic acid?
- Is water an omitted reactant, and H3O an omitted product within the general chemical equation?
2. Why did the 2I2 turn into I4?
3. Why are the caffeine, HI, and I4 joined with dots and not +? I know of hydrated ionic compounds, so are HI and I4 within the caffeine's structure, but not bonded to it? Why did a chemical reaction not occur between the three to create a new product?
4. Would KHSO4 be the "brown red" precipitate, or the other product? I cannot find a single other mention of C8H10N4O2.HI.I4 anywhere else on the internet.
Thank you to whoever offers guidance.