[AussieKenDoll]

What volume should I take when finding the concentration of acetic acid standardized with 0.1M NaOH
I titrated 5 ml of Acetic acid with 0.1 M NaOH and the average volume consumed = 26.05 mL
Consumed moles of NaOH = 2.605X10^(-3)
According to stoichiometry,
reacted Acetic acid moles = 2.605X10^(-3)
so the HAc concentration = {2.605X10^(-3)}/{(26.05+5)x10^(-3)} or {2.605X10^(-3)}/{(5)x10^(-3)}
Should I take the whole volume on the final solution or only the volume of A cetic acid when finding the concentration of acetic acid
I am not sure which volume should I take
HAc= Acetic acid

[Borek]

You are interested in the concentration of the original solution of which you used 5 mL.

[AussieKenDoll]

That means HAc concentration = {2.605X10^(-3)}/{(5)x10^(-3)} right?