I'm self-studying chem right now and was hoping someone could help me out with a specific electrochemistry problem:
Given a galvanic cell @ 25 C
o:
Pt(s)|H2(g, 1.0 bar)|H+(pH = ?)||Cl-(aq, 1.0M)|AgCl(s)|Ag(s), E = +0.30V
I need to find the PH on the left side of the cell.
(1) find half-reactions + combined rxnAgCl(s) + e
- Cl
-(aq) + Ag(s) (E
o=+0.22V)
0.5H
2(g)
H
+(aq) + e
- (E
o=0V)
so
AgCl(s) + 0.5H
2(g)
Cl
-(aq) + Ag(s) + H
+(aq)
(2) Use Nernst Equation to find [H+]ΔE = E
o - (RT/nF) * ln(Q)
(Expanding Q)
ΔE = E
o - (RT/nF) * ln([Cl
-][H
+] / [H
2]
0.5)
Knowns:
ΔE = +0.30V (given)
E
o = E
R - E
L = +0.22V - 0V = +0.22V
n = 1
[Cl
-] = 1.0 M (given)
[H
2] = 1.0 bar (given, but use P/RT = n/V to get in terms of M) = 1.0 / (0.08314 * 298.15) M
T = 298.15 K
R, F = constants
(3) Solve Nernst Equation symbolically and take -log to solve for unknown pH-log( e
((ΔE - Eo) / -(RT/F)) * ([H
2]
0.5 / [Cl
-])) = pH
This results in a calculated pH of 2, but the solution guide I'm using tells me the pH is 1. Is my issue here a fundamental misunderstanding of how to use the Nernst equation or do you think I'm just making a simple computation mistake somewhere when I plug in the values?
Any comments much appreciated!