A 40 l sample of N2 gas containing SO2 gas as an impurity was bubbled through a 3% solution of H2O2. The SO2 was converted to H2SO4 : SO2 + H2O2 --> H2SO4
A 25 ml portion of 0.01 mol/l NaOH was added to the solution, and the excess base was back-titrated with 13.6ml of 0.01 mol/l HCL. Calculate the ppm of SO2 ( that is, ml SO2/10^6ml sample) if the density of SO2 is 2.85g/l. (Atomic weights; H=1.0, N=14.0, O=16.0, Na=23.0, S=32.0 and Cl = 35.5)
My solution :
from this equation NaOH + HCl ---> Nacl + H2O ,mol of NaOH = 13.6*10^-5
from H2SO4 + 2NaOH ----> Na2SO4 +2H2O
I 25*10^-5
C -5.7*10^-5 -11.4*10^-5
E 13.6*10^-5
from SO2 + H2O2 ---> H2SO4
I 5.7*10^-5
C
E 5.7*10^-5
ppm = [(5.7*10^-5 *22.4)/40] *10^6
I got 31.92ppm but the answer is 32ppm. Did I make a mistake?