How much energy is released when 1 L of O2 reacts with excess sulphur at STP?
Now, I know that 1 L of O2 is 1.429 g, and 1.429 g of O2 = 0.04466 moles. What else do I do?
How do I find the energy??? Is this another PV=nRT question?
I'd try writing the equation, but I don't know the products. How do you guys always know the products?