[INeedSerotonin]

Hello

I've found this exercise ("Which one of these are optically active?"), but I just cannot understand how come (III) is optically active.



I know that (I) is optically active, because it has a chiral carbon. (II) has a geometric isomerism, and not an optical one. And what about (III)?

It doesn't make sense to me, because every single carbon is connected to at least 2 hydrogens, so it cannot be chiral, but the answer says (I) and (III) are optically active.

Could you guys please give me a hint here?

[AWK]

https://slideplayer.com/slide/9982508/32/images/53/1-Bromo-2-chlorocyclopropane.jpg

https://slideplayer.com/slide/9982508/

[INeedSerotonin]

Thanks! I will take a look at the links!