[1800chisaki]

i did the following;

n edta = c edta x V H2O
n edta = 0,01 x 250 ml = 2,5 mmol

do i need to multiply n by 2 since edta is a dihydrate? edta is in the H2Y2- form here

further: m edta = n edta x Mr edta
            m edta = 2,5 mmol x 372,24 mg/mmol = 930,6 g

[AWK]

2,5 mmol x 372,24 mg/mmol = 930,6 g

Wrong unit

[1800chisaki]

2,5 mmol x 372,24 mg/mmol = 930,6 g

Wrong unit

typo, but is my calculation correct? edta being a dihydrate doesnt change anything?

[AWK]

After all, you took into account the molar mass of dihydrate.