[JArchy123]

10L of a mixture of 5 mol percentage ethanol and 95 mol water. Required for the mixture are...

--L of industrial ethanol
-- of water

I am confused on how you calculate the volumes of each..

[jeffmoonchop]

You could do it by mass. The density of each are easily available.

[JArchy123]

I'm still confused

[JArchy123]

I already have the answers to the question:

1.5 L of ethanol
8.5 L of water

But can't figure it out

[JArchy123]

10L of a mixture of 5 mol percentage ethanol and 95 mol water. Required for the mixture are...

--L of industrial ethanol
-- of water

I am confused on how you calculate the volumes of each.

I already have the answers to the question:

1.5 L of ethanol
8.5 L of water

But can't figure it out

[Borek]

This is not entirely trivial due to the contraction - final volume is lower than the sum of volumes. Whether it matters or not depends on the accuracy required.

I would start by finding volumes required to make a mixture of 5 moles of ethanol and 95 moles of water - while that's not 10 L, that will give a correct ratio of volumes, easy to scale up.

[billnotgatez]

@Archy123
I combined your posts that are on the same topic
We only post a given question once on the forum.
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http://www.chemicalforums.com/index.php?topic=65859.0

[AWK]

What do you mean by industrial alcohol? Find its mass percentage, density, and density of water at the same temperature.
Convert the concentration of the diluted solution to mass percentage and find in the tables its density at the same temperature.
And you already have the trivial problem of mass percentage dilution in general chemistry.