To do the calculation for flask #1, it would be then:
15.15 mL - 0.20 mL = 14.98 mL which is 0.01498 L
0.01498L * 0.145 M HCl = 0.0021721 mol for HCl
Due to the ratio, it becomes 0.0021721 x 1/2 =0.001086 mol for Na2CO3
0.001086 mol Na2CO3 x molecular weight of 106 g/mol of Na2CO3 = 0.115 grams Na2CO3
(0.115 g/0.1554 g from given data)*100% = 74%
For flask #2,
29.88mL - 15.33mL = 14.55 mL which is 0.01455 L
0.01455 L * 0.145 M HCl = 0.00210975 mol HCl
0.00210975 mol HCl * 1/2 ratio = 0.00105 mol Na2CO3
0.00105 mol Na2CO3 * 106 g/mol Na2CO3 = 0.1118 grams Na2CO3
(0.1118 grams Na2CO3/0.1514g from given data) * 100% = 73.9%
Am I in the right spot for the calculations? Thank you for the help