[jennielynn_1980]

I am having trouble trying to figure out how to write the conjugate base for the following acids that I was given.  I have tried but I have no idea if they are right.  Is there a specific way to figure it out?

a)HCl base= Cl^-
b) CH₄ base= CH₃
c)HSO₃^- base = SO₃^2-
d)H₂SO₄ base = HSO₄^-
e)NH₃ base= NH₂
f)HClO₄ base=ClO₄^-

THanks

[Donaldson Tan]

LOL. It is not always the case of removing H, but actually a proton.

Check your charges for (b) and (e)

[phoebusvn]

NH₃ have NH₄^-

[Yggdrasil]

NH₂^- would be the conjugate base of NH₃ and NH₄⁺ would be the conjugate acid of NH₃.  NH₄^- does not exist.

[jennielynn_1980]

So for b) it would be CH₃^- and e) would be NH₂^-

Going back to geodome's comment, I know I just used that one rule of taking away a hydrogen but I am not sure of how else to do it.  Does anyone have an example where the simple removal of a hydrogen is not the answer so I have something else for an example?
Also, are the answers correct? 
Thanks

[Yggdrasil]

Geodome is just being very technical with his answer.  Removal of a hydrogen would mean removing a proton (hydrogen nucleus) and an electron to generate a radical (for example, removal of a hydrogen from HCl would generate a chlorine radical, Cl^.), whereas removal of just a proton would generate the chloride ion, Cl^-).