[shook0]

Hi, I'm supposed to set up a reaction between Cyclohexanol (I'm German, so I'm not sure if this spelling is correct in English) and K2Cr2O7. I thought it's a classical oxidation, however, the oxidation numbers don't change if I see it correctly. Can anybody help me please?

 C6H11OH + K2Cr2O7   ?

[Babcock_Hall]

Can you show us what your oxidation numbers are?

[shook0]

C6H11OH = C: +II; H +I; O: -II
The same applies to C6H11OOH

[Babcock_Hall]

Can you think of a different organic product?

[Borek]

C6H11OH = C: +II; H +I; O: -II
The same applies to C6H11OOH

No, ROOH contains an oxygen-oxygen bond, so these O don't have oxidation numbers of -2.

Not that it is an expected product of an alcohol oxidation.