[Dck140130]

Hello,

Could I theoretically mix 1 M of HBr with 1 M of H20 and then boil off the Br (BP = 58.8 C) and be left with H3O+?
                                             Δ
HBr + H20    H3O⁺ + Br       H30+

Any idea how long I would have to boil to ensure that all Br is boiled off?

[Aldebaran]

The short answer is no . Points to note: Br in the solution is Br^- ion . If Br could be released it would be Br₂ but that would involve breaking the covalent bond in gaseous HBr which you would not achieve by boiling.

[Ebbe Loos]

Hi

No, what you subcribed is not possible.

Another way to prove this, is by our knowlegde of solutions.

In a solution, this netto charge should be 0. This means if we add HBr to a solution, we get the next equation:
[Br-] + [OH-] = [H3O+]
If we remove the Br via gas, and keep the H3O+ the equation wouldnt be correct anymore, thus what you said doesnt happen.

But what happens if we boil a HBr solution? (If boiling implies 100°C)

The boilingpoint of water is 100°C, so the water (and thus solvent) will leave the reaction as gas. Leaving a oversatuared solution HBr.
This solution will push out HBr molecule in order to get rid of oversatuarating. Since the boiling point of HBr is something like -50°C, the HBr will also leave as gas.

Hope this helped!

[Aldebaran]

In fact hydrobromic acid forms a constant boiling point mixture at about 124 °C. So all the hydrogen bromide gas cannot be boiled off in a simple way.