I have the percentage uncertainty of a 0.15 M solution, but I don't know how to calculate the uncertainty for the 0.12, 0.09, 0.06 and 0.03 solutions, can someone help me?
Na2S2O3 Solution:
A 0.15 mol/dm3 solution of sodium thiosulfate was made by finding the mass amount of solid sodium thiosulfate needed to produce the solution using this formula
C = nv
C = Concentration (mol/L)
n = Mols
v = Volume (L)
0.15 = n1
n = 0.151
n = 0.15
Through this formula, it was found that 0.15 mols of sodium thiosulfate was needed. To find this amount in grams, this equation was used.
n = mMM
n = Mols
m = Mass (g)
MM = Molar mass (g/mol)
Molar mass of Sodium Thiosulfate, Na2S2O3 =(22.992) + (32.07 2) + (16.00 3)
= 158.12 g
0.15 = m158.12
m = 0.15158.12
m =23.718 g
23.718 g of sodium thiosulfate was measured on a scale then added to 1 L volumetric flask with water to make the 0.15 mol/L solution
1000 cm3 0.15 M Sodium Thiosulfate solution;
%uncertainty mass = 0.0123.718100 = 0.04216%
%uncertainty volume = 0.51000100= 0.05%
Total uncertainty =0.04216 +0.05 = 0.09216%