In the reaction represented by 3 Fe + 4 H2O → Fe3O4 + 4 H2, how many moles of H2 and what mass of Fe3O4 will be formed by the reaction of 5.10 moles of Fe?
a) 4 moles of H2 and 232g of Fe3O4 formed
b) 6.8 moles of H2 and 394g of Fe3O4 formed
c) 6.8 moles of H2 and 1.7 g of Fe3O4 formed
d) 20.4 moles of H2 and 1.18kg of Fe3O4 formed
(I got 6.8 moles of H2 by: 3moles Fe divided 5.10moles Fe ×4moles H2 = 6.8 moles of H2 and 1.18kg of Fe3O4 by 5.10x231.55 (molar mass of Fe3O4) but obviously this is not an option so I'm somewhat confused)