You're right. sorry. I meant 43.44 gmol is the molar mass of the CO2.
I was tired.
Okay, so
Nevermind, I'll just take a picture and upload it.
https://imgur.com/a/TPLbKOgAnd yes, I argued with the prof about the discrepancy, but he said "its just a matter of the mass of water being so large that the error by the air is going to be 0.01g" or something.
Cant remember it well.
Anyway, it made no sense at all to me. But yes, we were supposed to
[This is mass(Flask,stopper + water) - (Flask,stopper + air) = mass of water - ~~mass of air~~??]
Correct, Using 396.64 minus 131.4413 gets me mass of the water. Mass of the water / density gets me the .26573L.
Volume * density of the dry air, gets me the dry air that was put in at the beginning of the experiment, as 0.317g.
Using 0.317g and subtracting from 131.4413 gets me the mass of an empty (vacuum) flask with the stopper and plug, which therefore is subtracted from the CO2 flask of 131.6014 to get me mass of CO2 at 0.47712g.
At this point an equation m/V = PM / RT is used. I can plug in m, V, P, R, and so the remaining equation is 1.795507 = 0.041327 * M.
Then divide both sides by 0.041327, and get M = 43.44 g/mol, where M is the molar mass.