[Lilac12]

There is this question in a booklet I've been given that doesn't have any answers. I've tried to answer it but I don't even really know how to write the other half of the equation. I'll write in the question below:

"Write half-equations and hence a balance overall ionic equation for the reaction of acidified potassium dichromate solution and a solution of iron (ll) nitrate. (Note the potassium and nitrate ions are spectator ions)."

I'd really appreciate and explanation of how to get to the final answer.

[Hunter2]

Show your own ideas.
What is oxidiser, what is reducer?

[Lilac12]

I'm not sure how to directly respond to Hunter2, but the question he asked me is what I don't know, like how do I know what the reducing agent and oxidising agent is without knowing the other half of the equation. For example, a previous question in the booklet asked the same question, except it gave the balanced equation given to me of:
5Fe{2+} + MnO4{-} + 8H{+} --> 5Fe{3+} + Mn{2+} + 4H2O

So I knew that the oxidation was where electrons were lost, which was:
5Fe{2+} --> 5Fe{3+} + 5e

and the reduction was where electrons were gained, which was:
MnO4{-} + 8H{+} + 5e --> Mn{2+} + 4H2O

So if I knew the whole equation I would know how to write out each half equation, so really my question is how do I do my question I posted without knowing the equation?

[Hunter2]

Well, some background you have to learn. Here refer to permanganate and it's behaviour. It's normally an oxidiser. Iron II is the reducer.
Oxidiser gain electrons, reducer donate electrons.
Permanganate has oxidation number +7 for manganese. It will go down to +2 if acidic condition for example.iron exists normally in +2  and +3.

Check here as well

https://chemicalforum.webqc.org/viewtopic.php?t=21374

[Aldebaran]

Seems like a structured introductory text about redox might be helpful for you. Have a look at this link and come back if you need further help: https://www.chemguide.co.uk/inorganic/redoxmenu.html

[Lilac12]

Thank you for all the help, I think I've gotten to the answer now!