[udo.sopon]

I've trying to calculate the free chlorine (Cl-) standard solution from dichloroisocyanuric acid sodium salt. According to Merck. The answer is 1.850 g in 1000 mL of water for free chlorine concentration as 1000 mg/l.

I try to calculate and get answer 1.805.

255.989 g/mol of total / 2* (35.45 g/mol of Cl) *2(ratio of mol) = 1.805 g

Could any one suggest me for correct calculation please? Thank in advance.

[Hunter2]

Mathematically

1 g/l Cl2/ 71 g/ mol = x g/l/256 g/ mol

x = 3,6 g/l means the double of the number what you got.

[Borek]

1.805 vs 1.850 on the Merck's page  looks like a typo, but - as it was already signaled - it doesn't make sense from the stoichiometric point of view. Dissolving 1.805 g of the salt in 1 L of water produces solution that is 500 mg/L in chlorine (assuming complete hydrolysis).