[777888]

I have some questions! Hope someone can help me Thank you

1)"An aqueous chlorine solution is added to a phosphorous acid solution"

Would the species initally present be: Cl2, H2O, H+, H3PO3 ?  
INSTEAD OF: Cl2, H2O, H+, PO3(3-) ?
Becuase I can't find PO3(3-) in the redox table.



2)Question: Gold is added to an hydrochloric acid solution. Predict the redox reaction and determine if it's spontaneous.

Steps:
Species initally present: Au  H+  Cl-    H2O

By choosing the strongest reducing/oxidizing agents, and add the half-reactions together, I got the equation:

4H(+) +2H2O->2H2+O2+4H(+)  
2H2O->2H2+O2    Subtract  4H(+) from both sides.

Problem: Would this be spontaneous?? How can I know this by the equation? (There's only 1 reactant in the net equation so I don't know how to determine which is oxidizing agent and which is reducing agent...)

3)Would the Cu-Fe cell's(Cu and Fe as electrodes, CuCl2, FeSO4 as electrolytes, and the salt bridge contains KNO3) cell potential be 0.34-(-0.44)=0.78 V?

[bg1047]

Phospohric acid is HPO4(3-) not HPO3(3-).

To determine if it is spontaneous calculate the Delta G for the RXn and if it in Negative it is spontaneous.

[AWK]

Chlorine will oxidise phosporous acid to phosphoric acid.
H3PO3 is a diprotic acid and PO3(3-) does not exist.

[Donaldson Tan]

H₃PO₃ is dibasic in virtue of its structure:

                H
                |
            O=P(O-H)₂

Only the hydrogen attached to the oxygen atoms are capable being released into solution as H⁺

For your gold question, just work out E_cell. It should be negative, ie. the reaction isn't spontaneous, because gold is less reactive than copper with bronsted acid.