[cutiepie2]

  ok i am needing some help PLEASE i suppose that is obvious tho right? thats kinda why most of us are here no? well i was wonderin gif you could tell me if i got the following questions right or not.
3. find the number of atoms in a) 1.5 mol of carbo i got 7.5 time 10 to the 22 is that right?
b) 1.5 mol of carbon dioxide i got 2.05 times 10 to the 22 is this right?

and then find the volume of a  gas at -30 degrees celsius and 0.75 atm if it occupies a volume of 255L at 40.0 degrees celsius and 1.25 atm. i got two possible answers here is either correct i got 411.42 L and 330 L.
thanks any help would be appreciated!
ok sorry im a dumby haha yeah i meant carbon not carbo OOOPPSIEs
anyway for the a and b i did 1.5 molover 12.011g * 6.02 *10 to the 23 over 1mol im thinking i need to take the 12.011g out right??? and then for b) i did 1.5mol *6.02*1023 over 1 mol *1g over 44.011.
and for question 4 one of the answers is right then!? YEAH! im thinking the rigth answer is 411.42 right?

[Dan]

3. find the number of atoms in a) 1.5 mol of carbo i got 7.5 time 10 to the 22 is that right?
b) 1.5 mol of carbon dioxide i got 2.05 times 10 to the 22 is this right?

Both incorrect. Can you show your working?
Remember, 1 mol = 6.022 x 10²³

and then find the volume of a  gas at -30 degrees celsius and 0.75 atm if it occupies a volume of 255L at 40.0 degrees celsius and 1.25 atm. i got two possible answers here is either correct i got 411.42 L and 330 L.

How did you arrive at these different values? Show working.

use pV=nRT

1) find n using the data for the gas at 40 degrees C and 1.25 atm.
2) now that you have n, solve for V using the first set of data.

One of the answers you gave is correct, which is it?

Edit: this is a long winded way of doing what Alberto has posted below...

[Alberto_Kravina]

and then find the volume of a  gas at -30 degrees celsius and 0.75 atm if it occupies a volume of 255L at 40.0 degrees celsius and 1.25 atm. i got two possible answers here is either correct i got 411.42 L and 330 L.

Have you ever heard about the gas equation p₁*V₁ / T₁ = p₂*V₂ / T₂

3. find the number of atoms in a) 1.5 mol of carbo i got 7.5 time 10 to the 22 is that right?
b) 1.5 mol of carbon dioxide i got 2.05 times 10 to the 22 is this right?

a.)Assuming that you mean CARBON, the answer seems to be wrong, show us how you got your answer...
b.)This one is also wrong

Edit: Dan was faster 

[cutiepie2]

okay so you guys i put how i did things up above PLEASE *delete me*

[Dan]

anyway for the a and b i did 1.5 molover 12.011g * 6.02 *10 to the 23 over 1mol im thinking i need to take the 12.011g out right??? and then for b) i did 1.5mol *6.02*1023 over 1 mol *1g over 44.011.

I have no idea what you're up to there.

OK. A mole is a quantity, nothing more. 1 mol is 6.022 x 10²³ items, in the same way that a dozen is 12 items or a pair is two items.

So, answer me these questions, showing working

how many eggs in 1.5 dozen eggs?
how many fingers on 1.5 pairs of hands?

Now use the same method to  solve the mole problem.

and for question 4 one of the answers is right then!? YEAH! im thinking the rigth answer is 411.42 right?

Show working.

[cutiepie2]

ok i did the other questions over and got 9.03 times 10 to the 23 and i redid the question 4 and got about 290 L by doing o.75 / 273+-30 = 1.25 times 225 / 273 + 40 thats the work

[Dan]

ok i did the other questions over and got 9.03 times 10 to the 23

ok, thats 3a) done, how about 3b)?

and i redid the question 4 and got about 290 L by doing o.75 / 273+-30 = 1.25 times 225 / 273 + 40 thats the work

That equation is meaningless, where is your unknown V?