[UnconciousPilot]

Simple question.. I just can't figure out what it goes to when titrated with NaOH,

I thought it was just something like H2C2O4•2H2O + NaOH --> NaHC2O4•2H2O + H2O however according to my experiment results, there should be a 2:1 ratio of the NaOH and the acid and I have no idea how to deal with the attached water molecules...

Any input is appreciated, thanks.

[Alberto_Kravina]

Forget about the attached water molecules in the crystal, as they are irrelevant during the reaction.
So just write H₂C₂O₄*2H₂O as H₂C₂O₄ and that's it.

[UnconciousPilot]

Alright fair enough, I just figured out why I needed a 2:1 ratio too... 2 protons... Titration calls for a complete neutralization  whoops.