Consider the equilibrium represented by the following equation:
Heat + H2O(l) H2O(g) in which T=373 K, P= 101 kPa
Which of the following will favour the reverse reaction?
a) The total volume of the system is increased
b) Boiling water is added to the system
c) Water vapour is removed from the system
d) The system is cooled
I think that the answer is c) becasue you originally had heat plus water(in liquid form) and the forward reaction is the gaseous state. Can someone please tell me if I am on the right track?
a,b,c, are wrong. Therefore, you can assume d is correct (but you really need to know whether its endo or exothermic rxn to be really sure)
a) if you increase the volume of the sys, the pressure goes down. Therefore, to restore equilibrium you will shift the equilibrium in the forward direction to "make" more gas molecules.
b) boiling water = liquid water is added to system. Therefore, equilibrium will shift to the forward direction.
c) removing water vapour decrease [H2O(g)]. Therefore, equilibrium will shift to the forward direction.