Hello,
How the question is carried out is the same in most situations. The only main factors are what your knowns and unknowns are. The example you provided was:
N2 + 3 H2 ----> 2NH3
m=0.750g
M=28.02g/mole
but because you gave no masses or anything of the like I'm going to use my own numbers, added below the equation how I would normally do it.
For this I'm going to assume that you know the mass of N2 used in the reaction and are trying to find out the mass of NH3 produced in the reaction. The general steps used are:
1) find the number of moles of N2
n=m/M
=0.750g/28.02g/mole
=2.6766...x10^-2 mole N2
2) do a mole ratio
# of mole N2 * (# of mole of what you what to know / # of mole of what you know)
for this question it will be, for the second part, 2NH3 / N2 because we know how many moles there are of N2 but not NH3, also we use the mole ratio for the balanced equation
=2.6766...x10^-2 mole * 2 mole NH3 / 1 mole N2
=5.3533...x10^-2 mole NH3
3) now that we know how many moles of NH3 are produced, we can calculate the mass of NH3 produced
n=m/M
m=Mn
=5.3533...x10^-2 mole * 17.04 g/mole
=0.912g
Then your done. The same general flow of it can be used for any calculation like that, regardless of your knowns and unknowns.
I'm going to cross my fingers that that is what you were wondering about, either way, that's how I took your question. Try to be more exact on what your question is.
Have fun and good luck.
X-18