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2H2SO4-2
If I am balancing using the half reaction method, how would I balance something with 2 reactants and 3 products or 1 reactant and 2 products?
just to confirm, when I'm balancing an ion say 2H2SO4 -2, I'm using -4 (2 x -2) as the oxidation #, not -8 (4 x -2), right?