[toxic_ninja]

23.0 g(0.5 M) of ethanol was reacted with 60.0g(1.0 M) of ethanoic acid and the reaction allowed to reach equilibrium at 373 K. 37.0g (0.42 M ) of ethyl ethanoate was found to be present in the equilibrium mixture. Calculate K to the nearest integer.

I understand this to some part... I put the products over reactants, therefore I have (0.42/V) x (0.42/V) / (0.08/ V) x (0.58/V) =

Where do I get my V from??

I know this seems like a very stupid question, but can someone please answer?

Thanks in Advance

[Borek]

Check if it will not cancel out

[toxic_ninja]

Oh....That was...obvious...

THanks