I calculated this problem but I don't think it's right, please let me know!!!!!!!!
Determine Ph of a 0.15 m solution of KF (ka=7.0x10-4)
my calculations: 7.0x10-4/0.15 = 4.66x10-3
Log of 4.66x10-3= 2.33
It doen't seem to me that it's correct but I wanna check if I set it up correctly!
Thanks in advance!!